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SOLVED:Consider the flow down a prismatic channel having a rectangular cross section of width b. The channel bottom makes an angle θwith the horizontal. Show that (d y)/(d x)=(tanθ-(n^2 Q^2) /(A^2 Rh^4 / 3κ^2))/(1-Q^2 /(A^2 g y cos ^2θ)) where y is the vertical fluid depth, A=b y cosθ, ard Q is the volume flow rate. Discuss the form of the equation for small values of θ(θ∼1^∘)
SOLVED:Consider the flow down a prismatic channel having a rectan…
Jun 10, 2020
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